“216 TMA 01 Question 3 This lab asks you to design and apply an IPv4 addressing scheme to the network shown in Figure 1 given the network address 192.168.1.0/24. You should use equal size subnets and use the smallest size of subnet possible given the following requirements: The LAN connected to router R1 will require enough IP addresses to accommodate 15 hosts (including the router). The LAN connected to router R2 will require enough IP addresses to accommodate 30 hosts (including the router). The link between R1 and R2 will require IP addresses at the end of each link. Subnet the Address Space a) Design a subnetting scheme and answer the following questions: i) Into how many equally sized subnets must the given network address be divided to give the maximum number of subnets? Show your working. ii) Give the subnet mask for this network in dotted decimal and slash formats. iii) How many useable hosts are available in each subnetwork? Briefly justify your answer. (8 marks) Reflect upon the suitability of the configuration f) Subnetting was developed to make more efficient use of the limited number of IPv4 addresses available. Do you consider this network subnetting scheme makes efficient use of the available addresses or not? Whatever your decision, you should justify it in terms of complexity, numbers of unused hosts, equipment needs, et cetera. You will be penalised if your decision about efficient use of addresses is not stated clearly. b) Apply your addressing scheme using the following instructions. Hence complete Table (Note: Subnets number from 0 upwards) i) Assign the second subnet to the LAN attached to R1 (R1LAN). ii) Assign the third subnet to the serial link between R1 and R2 (R1-R2). ii) Assign the fourth subnet to the LAN attached to R2 (R2LAN).”

i) There is 1 x LAN connected to router R1 and 1 x LAN connected to router R2.  1 x subnet will therefore be required to service the host requirements of each LAN.  Additionally, a subnet will be required for the link between routers R1 and R2 and so 3 subnets in total will need to be created from the network address 192.168.1.0/24.  However, the question suggests that rather than needing a maximum of 4 subnets with larger host address capability – which is the smallest number of subnets possible to accommodate 3 subnets using the formula  2^n (where n = the number of bits borrowed) –  a larger amount of subnets but with the smallest number of hosts per subnet, is preferable.  In this case R2LAN has the largest requirement of 30 hosts, and if all subnets are all to be of equal size, the smallest number of hosts per subnet is therefore 30.

To find the number of bits needed to provide 8…(short extract)

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